Re: p. 164 apologies if that confused you. I don’t think that two is supposed to be there at all: if is is, the example makes a mistake by forgetting about it.

For later on, the example on p.115 will be important.

OK. So

is good. Now apply boundary conditions:

Now you have to carefully multiply out:

,

so, for your problem

and the p.115 example comes into play.

Regards,

J.P.

I’ve started assignment two and just have a question regarding the first question. The second derivative is multiplied by m, which in my case is 6. So it’s:

I’ve looked through the notes and on page 164 there is a similar question and it’s multiplied by 2, in the solution then the 2 is left out in the second step so is this the same case. Or is it a shifted equation? I’ve attached what I’ve done.

]]>Careful! You have:

not .

As you have you have a Rule I and a Rule II.

The Rule I gives a term of the form:

The Rule II gives terms of the form:

Therefore you need:

.

Hope this helps.

Regards,

J.P.

I’m doing the question 3(a) from Problem B but I’m stuck when I have to find the partial fractions.

I found over so it’s Rule 2 but I don’t know what to put for the numerator, and as written in the manual, or , , and , because I have 3 factors.

I attached my draft to the email.

Regards.

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