In a recent preprint, Haonan Zhang shows that if (where
is a Sekine Finite Quantum Group), then the convolution powers,
, converges if
.
The algebra of functions is a multimatrix algebra:
.
As it happens, where , the counit on
is given by
, that is
, dual to
.
To help with intuition, making the incorrect assumption that is a classical group (so that
is commutative — it’s not), because
, the statement
, implies that for a real coefficient
,
,
as for classical groups .
That is the condition is a quantum analogue of
.
Consider a random walk on a classical (the algebra of functions on is commutative) finite group
driven by a
.
The following is a very non-algebra-of-functions-y proof that implies that the convolution powers of
converge.
Proof: Let be the smallest subgroup of
on which
is supported:
.
We claim that the random walk on driven by
is ergordic (see Theorem 1.3.2).
The driving probability is not supported on any proper subgroup of
, by the definition of
.
If is supported on a coset of proper normal subgroup
, say
, then because
, this coset must be
, but this also contradicts the definition of
.
Therefore, converges to the uniform distribution on
Apart from the big reason — that this proof talks about points galore — this kind of proof is not available in the quantum case because there exist that converge, but not to the Haar state on any quantum subgroup. A quick look at the paper of Zhang shows that some such states have the quantum analogue of
.
So we have some questions:
- Is there a proof of the classical result (above) in the language of the algebra of functions on
, that necessarily bypasses talk of points and of subgroups?
- And can this proof be adapted to the quantum case?
- Is the claim perhaps true for all finite quantum groups but not all compact quantum groups?
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